Identification
Test solution
Disperse a quantity of Ivermectin Paste containing about 5 mg of ivermectin, accurately weighed, in 10 mL of methanol, sonicating if necessary until completely dispersed.
Application volume:
2 µL.
Developing solvent system:
a mixture of methylene chloride, methanol, and ammonium hydroxide (90:9:1).
Procedure
Develop the chromatogram in an unsaturated chamber. Remove the plate, allow to air-dry, and examine under short- and long-wavelength UV light.
B:
The retention times of the two principal component peaks of ivermectin in the chromatogram of the Assay preparation correspond to those of the two principal component peaks of ivermectin in the chromatogram of the Standard preparation, as obtained in the Assay.
Chromatographic purity
Mobile phase and Chromatographic system
Proceed as directed in the Assay.
Standard solution
Dissolve an accurately weighed quantity of
USP Ivermectin RS in methanol, and dilute quantitatively, and stepwise if necessary, with methanol to obtain a solution having a concentration of 0.004 mg per mL.
Test solution
Disperse a quantity of Ivermectin Paste, accurately weighed, in methanol, sonicating if necessary, to obtain a solution containing 0.4 mg of ivermectin per mL, based on the label claim.
Procedure
Inject equal volumes (about 20 µL) of the
Test solution and the
Standard solution into the chromatograph, record the chromatogram, and measure all of the peak responses. Calculate the percentage of each impurity in the portion of Paste taken by the formula:
100(CS / CT)(ri / rS)
in which
CS is the concentration, in mg per mL, of ivermectin in the
Standard solution; CT is the concentration, in mg per mL, of ivermectin in the
Test solution; ri is the peak response for each impurity obtained from the
Test solution; and
rS is the ivermectin peak response obtained from the
Standard solution. Not more than 2.7% of the peak with a relative retention time of about 1.3 to 1.5 (relative to that of the principal peak) is found; not more than 1.0% of any other impurity is found; and not more than 6.0% of total impurities is found. Disregard any peak below 0.05%.
Assay
Mobile phase
Prepare a filtered and degassed mixture of acetonitrile, methanol, and water (106:55:39). Make adjustments if necessary (see
System Suitability under
Chromatography
621
).
Standard preparation
Dissolve an accurately weighed quantity of
USP Ivermectin RS in methanol, and dilute quantitatively, and stepwise if necessary, with methanol to obtain a solution having a known concentration of about 0.4 mg per mL.
Assay preparation
Disperse a quantity of Ivermectin Paste, accurately weighed, in methanol, sonicating, if necessary, to obtain a solution containing 0.4 mg of ivermectin per mL.
Chromatographic system (see Chromatography
621
)
The liquid chromatograph is equipped with a 245-nm detector and a 4.6-mm × 25-cm column that contains 5-µm packing L1. The flow rate is about 1.5 mL per minute. Chromatograph the
Standard preparation, and record the peak responses as directed for
Procedure: the resolution,
R, between the first peak (component H
2B
1b) and the second peak (component H
2B
1a) is not not less than 3.0; and the relative standard deviation for replicate injections is not more than 2.0%, determined from the component H
2B
1a peak.
Procedure
Separately inject equal volumes (about 20 µL) of the
Standard preparation and the
Assay preparation into the chromatograph, record the chromatograms, and measure the responses for the component H
2B
1a plus component H
2B
1b. Calculate the percentage of the label claim for ivermectin (H
2B
1a + H
2B
1b) in the portion of Paste taken by the formula:
100(CS / CU)(rU / rS)
in which
CS is the concentration, in mg per mL, of
USP Ivermectin RS in the
Standard preparation; CU is the concentration, in mg per mL, of ivermectin in the
Assay preparation; rU is the total response of the H
2B
1a plus H
2B
1b peaks obtained from the
Assay preparation; and
rS is the total peak response of the H
2B
1a plus H
2B
1b peaks obtained from the
Standard preparation. Calculate the ratio of the contents, in percentage, of H
2B
1a / (H
2B
1a + H
2B
1b) in the portion of Paste taken by the formula:
100(r1a / rU)
in which
r1a is the peak response of H
2B
1a obtained from the
Assay preparation, and
rU is as described above.